Optimal. Leaf size=159 \[ -\frac {65 x}{16 a^4}-\frac {65 \cot (c+d x)}{16 a^4 d}-\frac {4 i \log (\sin (c+d x))}{a^4 d}+\frac {31 \cot (c+d x)}{48 a^4 d (1+i \tan (c+d x))^2}+\frac {2 \cot (c+d x)}{a^4 d (1+i \tan (c+d x))}+\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3} \]
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Rubi [A]
time = 0.30, antiderivative size = 159, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {3640, 3677,
3610, 3612, 3556} \begin {gather*} -\frac {65 \cot (c+d x)}{16 a^4 d}-\frac {4 i \log (\sin (c+d x))}{a^4 d}+\frac {2 \cot (c+d x)}{a^4 d (1+i \tan (c+d x))}+\frac {31 \cot (c+d x)}{48 a^4 d (1+i \tan (c+d x))^2}-\frac {65 x}{16 a^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3}+\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4} \end {gather*}
Antiderivative was successfully verified.
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Rule 3556
Rule 3610
Rule 3612
Rule 3640
Rule 3677
Rubi steps
\begin {align*} \int \frac {\cot ^2(c+d x)}{(a+i a \tan (c+d x))^4} \, dx &=\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {\int \frac {\cot ^2(c+d x) (9 a-5 i a \tan (c+d x))}{(a+i a \tan (c+d x))^3} \, dx}{8 a^2}\\ &=\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3}+\frac {\int \frac {\cot ^2(c+d x) \left (68 a^2-56 i a^2 \tan (c+d x)\right )}{(a+i a \tan (c+d x))^2} \, dx}{48 a^4}\\ &=\frac {31 \cot (c+d x)}{48 a^4 d (1+i \tan (c+d x))^2}+\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3}+\frac {\int \frac {\cot ^2(c+d x) \left (396 a^3-372 i a^3 \tan (c+d x)\right )}{a+i a \tan (c+d x)} \, dx}{192 a^6}\\ &=\frac {31 \cot (c+d x)}{48 a^4 d (1+i \tan (c+d x))^2}+\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3}+\frac {2 \cot (c+d x)}{d \left (a^4+i a^4 \tan (c+d x)\right )}+\frac {\int \cot ^2(c+d x) \left (1560 a^4-1536 i a^4 \tan (c+d x)\right ) \, dx}{384 a^8}\\ &=-\frac {65 \cot (c+d x)}{16 a^4 d}+\frac {31 \cot (c+d x)}{48 a^4 d (1+i \tan (c+d x))^2}+\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3}+\frac {2 \cot (c+d x)}{d \left (a^4+i a^4 \tan (c+d x)\right )}+\frac {\int \cot (c+d x) \left (-1536 i a^4-1560 a^4 \tan (c+d x)\right ) \, dx}{384 a^8}\\ &=-\frac {65 x}{16 a^4}-\frac {65 \cot (c+d x)}{16 a^4 d}+\frac {31 \cot (c+d x)}{48 a^4 d (1+i \tan (c+d x))^2}+\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3}+\frac {2 \cot (c+d x)}{d \left (a^4+i a^4 \tan (c+d x)\right )}-\frac {(4 i) \int \cot (c+d x) \, dx}{a^4}\\ &=-\frac {65 x}{16 a^4}-\frac {65 \cot (c+d x)}{16 a^4 d}-\frac {4 i \log (\sin (c+d x))}{a^4 d}+\frac {31 \cot (c+d x)}{48 a^4 d (1+i \tan (c+d x))^2}+\frac {\cot (c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {7 \cot (c+d x)}{24 a d (a+i a \tan (c+d x))^3}+\frac {2 \cot (c+d x)}{d \left (a^4+i a^4 \tan (c+d x)\right )}\\ \end {align*}
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Mathematica [B] Both result and optimal contain complex but leaf count is larger than twice
the leaf count of optimal. \(444\) vs. \(2(159)=318\).
time = 2.96, size = 444, normalized size = 2.79 \begin {gather*} \frac {i \csc (c) \sec ^4(c+d x) (\cos (d x)+i \sin (d x))^4 \left (1536 d x \cos ^3(c)+4608 i d x \cos ^2(c) \sin (c)+1536 i \text {ArcTan}(\tan (d x)) \sin (c) (\cos (4 c)+i \sin (4 c))-64 \cos (c) \left (24 d x \cos (4 c)+24 i d x \sin (4 c)+\sin ^2(c) (72 d x-i \cos (6 d x)-\sin (6 d x))\right )+i \left (-192 i \cos (4 c-d x) \csc (c+d x)+192 i \cos (4 c+d x) \csc (c+d x)+1560 d x \cos (4 c) \sin (c)+864 i \cos (2 c) \cos (2 d x) \sin (c)+180 i \cos (4 d x) \sin (c)+32 i \cos (2 c) \cos (6 d x) \sin (c)+3 i \cos (4 c) \cos (8 d x) \sin (c)+768 i \cos (4 c) \log \left (\sin ^2(c+d x)\right ) \sin (c)-1536 d x \sin ^3(c)-864 \cos (2 d x) \sin (c) \sin (2 c)+1560 i d x \sin (c) \sin (4 c)+3 \cos (8 d x) \sin (c) \sin (4 c)-768 \log \left (\sin ^2(c+d x)\right ) \sin (c) \sin (4 c)+864 \cos (2 c) \sin (c) \sin (2 d x)+864 i \sin (c) \sin (2 c) \sin (2 d x)+180 \sin (c) \sin (4 d x)+32 \cos (2 c) \sin (c) \sin (6 d x)+3 \cos (4 c) \sin (c) \sin (8 d x)-3 i \sin (c) \sin (4 c) \sin (8 d x)+192 \csc (c+d x) \sin (4 c-d x)-192 \csc (c+d x) \sin (4 c+d x)\right )\right )}{384 a^4 d (-i+\tan (c+d x))^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.39, size = 109, normalized size = 0.69
method | result | size |
derivativedivides | \(\frac {\frac {17 i}{16 \left (\tan \left (d x +c \right )-i\right )^{2}}-\frac {i}{8 \left (\tan \left (d x +c \right )-i\right )^{4}}+\frac {129 i \ln \left (\tan \left (d x +c \right )-i\right )}{32}+\frac {5}{12 \left (\tan \left (d x +c \right )-i\right )^{3}}-\frac {49}{16 \left (\tan \left (d x +c \right )-i\right )}-\frac {1}{\tan \left (d x +c \right )}-4 i \ln \left (\tan \left (d x +c \right )\right )-\frac {i \ln \left (\tan \left (d x +c \right )+i\right )}{32}}{d \,a^{4}}\) | \(109\) |
default | \(\frac {\frac {17 i}{16 \left (\tan \left (d x +c \right )-i\right )^{2}}-\frac {i}{8 \left (\tan \left (d x +c \right )-i\right )^{4}}+\frac {129 i \ln \left (\tan \left (d x +c \right )-i\right )}{32}+\frac {5}{12 \left (\tan \left (d x +c \right )-i\right )^{3}}-\frac {49}{16 \left (\tan \left (d x +c \right )-i\right )}-\frac {1}{\tan \left (d x +c \right )}-4 i \ln \left (\tan \left (d x +c \right )\right )-\frac {i \ln \left (\tan \left (d x +c \right )+i\right )}{32}}{d \,a^{4}}\) | \(109\) |
risch | \(-\frac {129 x}{16 a^{4}}-\frac {9 i {\mathrm e}^{-2 i \left (d x +c \right )}}{4 a^{4} d}-\frac {15 i {\mathrm e}^{-4 i \left (d x +c \right )}}{32 a^{4} d}-\frac {i {\mathrm e}^{-6 i \left (d x +c \right )}}{12 a^{4} d}-\frac {i {\mathrm e}^{-8 i \left (d x +c \right )}}{128 a^{4} d}-\frac {8 c}{a^{4} d}-\frac {2 i}{d \,a^{4} \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}-\frac {4 i \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{a^{4} d}\) | \(132\) |
norman | \(\frac {-\frac {7 i \left (\tan ^{5}\left (d x +c \right )\right )}{d a}-\frac {1}{d a}-\frac {949 \left (\tan ^{4}\left (d x +c \right )\right )}{48 d a}-\frac {715 \left (\tan ^{6}\left (d x +c \right )\right )}{48 d a}-\frac {65 \left (\tan ^{8}\left (d x +c \right )\right )}{16 d a}-\frac {65 x \tan \left (d x +c \right )}{16 a}-\frac {65 x \left (\tan ^{3}\left (d x +c \right )\right )}{4 a}-\frac {195 x \left (\tan ^{5}\left (d x +c \right )\right )}{8 a}-\frac {65 x \left (\tan ^{7}\left (d x +c \right )\right )}{4 a}-\frac {65 x \left (\tan ^{9}\left (d x +c \right )\right )}{16 a}-\frac {175 \left (\tan ^{2}\left (d x +c \right )\right )}{16 d a}-\frac {2 i \left (\tan ^{7}\left (d x +c \right )\right )}{d a}-\frac {14 i \tan \left (d x +c \right )}{3 d a}-\frac {26 i \left (\tan ^{3}\left (d x +c \right )\right )}{3 d a}}{\tan \left (d x +c \right ) a^{3} \left (1+\tan ^{2}\left (d x +c \right )\right )^{4}}-\frac {4 i \ln \left (\tan \left (d x +c \right )\right )}{a^{4} d}+\frac {2 i \ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{a^{4} d}\) | \(269\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.38, size = 136, normalized size = 0.86 \begin {gather*} -\frac {3096 \, d x e^{\left (10 i \, d x + 10 i \, c\right )} - 24 \, {\left (129 \, d x - 68 i\right )} e^{\left (8 i \, d x + 8 i \, c\right )} + 1536 \, {\left (i \, e^{\left (10 i \, d x + 10 i \, c\right )} - i \, e^{\left (8 i \, d x + 8 i \, c\right )}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right ) - 684 i \, e^{\left (6 i \, d x + 6 i \, c\right )} - 148 i \, e^{\left (4 i \, d x + 4 i \, c\right )} - 29 i \, e^{\left (2 i \, d x + 2 i \, c\right )} - 3 i}{384 \, {\left (a^{4} d e^{\left (10 i \, d x + 10 i \, c\right )} - a^{4} d e^{\left (8 i \, d x + 8 i \, c\right )}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.37, size = 252, normalized size = 1.58 \begin {gather*} \begin {cases} \frac {\left (- 442368 i a^{12} d^{3} e^{18 i c} e^{- 2 i d x} - 92160 i a^{12} d^{3} e^{16 i c} e^{- 4 i d x} - 16384 i a^{12} d^{3} e^{14 i c} e^{- 6 i d x} - 1536 i a^{12} d^{3} e^{12 i c} e^{- 8 i d x}\right ) e^{- 20 i c}}{196608 a^{16} d^{4}} & \text {for}\: a^{16} d^{4} e^{20 i c} \neq 0 \\x \left (\frac {\left (- 129 e^{8 i c} - 72 e^{6 i c} - 30 e^{4 i c} - 8 e^{2 i c} - 1\right ) e^{- 8 i c}}{16 a^{4}} + \frac {129}{16 a^{4}}\right ) & \text {otherwise} \end {cases} - \frac {2 i}{a^{4} d e^{2 i c} e^{2 i d x} - a^{4} d} - \frac {129 x}{16 a^{4}} - \frac {4 i \log {\left (e^{2 i d x} - e^{- 2 i c} \right )}}{a^{4} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 1.24, size = 129, normalized size = 0.81 \begin {gather*} -\frac {\frac {1536 i \, \log \left (-i \, \tan \left (d x + c\right )\right )}{a^{4}} + \frac {12 i \, \log \left (i \, \tan \left (d x + c\right ) - 1\right )}{a^{4}} - \frac {1548 i \, \log \left (-i \, \tan \left (d x + c\right ) - 1\right )}{a^{4}} + \frac {384 \, {\left (-4 i \, \tan \left (d x + c\right ) + 1\right )}}{a^{4} \tan \left (d x + c\right )} + \frac {3225 i \, \tan \left (d x + c\right )^{4} + 14076 \, \tan \left (d x + c\right )^{3} - 23286 i \, \tan \left (d x + c\right )^{2} - 17404 \, \tan \left (d x + c\right ) + 5017 i}{a^{4} {\left (\tan \left (d x + c\right ) - i\right )}^{4}}}{384 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 4.16, size = 165, normalized size = 1.04 \begin {gather*} \frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,129{}\mathrm {i}}{32\,a^4\,d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,1{}\mathrm {i}}{32\,a^4\,d}-\frac {\frac {1}{a^4}-\frac {851\,{\mathrm {tan}\left (c+d\,x\right )}^2}{48\,a^4}+\frac {65\,{\mathrm {tan}\left (c+d\,x\right )}^4}{16\,a^4}+\frac {\mathrm {tan}\left (c+d\,x\right )\,26{}\mathrm {i}}{3\,a^4}-\frac {{\mathrm {tan}\left (c+d\,x\right )}^3\,57{}\mathrm {i}}{4\,a^4}}{d\,\left ({\mathrm {tan}\left (c+d\,x\right )}^5-{\mathrm {tan}\left (c+d\,x\right )}^4\,4{}\mathrm {i}-6\,{\mathrm {tan}\left (c+d\,x\right )}^3+{\mathrm {tan}\left (c+d\,x\right )}^2\,4{}\mathrm {i}+\mathrm {tan}\left (c+d\,x\right )\right )}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )\right )\,4{}\mathrm {i}}{a^4\,d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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